Solution — Cs50 Tideman

// Iterate over each pair (strongest to weakest) for (int i = 0; i < pair_count; i++)

To ensure fairness, pairs are sorted in descending order based on their "strength of victory" (the number of voters who preferred the winner). You can use standard sorting algorithms like or Selection Sort here, using the values in the preferences array as your sorting key. Stack Overflowhttps://stackoverflow.com CS50 pset 3: Tideman sort_pairs function - Stack Overflow Cs50 Tideman Solution

After adding winner→loser, does loser have a path to winner in current locked graph? Yes → cycle. // Iterate over each pair (strongest to weakest)

return true;

# Update vote counts vote_counts = candidate: 0 for candidate in candidates for pair in pairs: if len(pair) > 0: vote_counts[pair[0]] += 1 Yes → cycle

int winner = check_for_winner(candidates_list, candidates); while (winner == -1) // Eliminate candidate with fewest votes int eliminated = -1; int min_votes = voters + 1; for (int i = 0; i < candidates; i++) if (candidates_list[i].votes < min_votes) min_votes = candidates_list[i].votes; eliminated = candidates_list[i].id;